Block `A` in the figure is released from the rest when the extension in the spring is `x_(0)`. The maximum downward displacement of the block will be `:`

Options

A. `(Mg)/(2k)-x_(0)`
B. `(Mg)/(2k)+x_(0)`
C. `(2Mg)/(k)-x_(0)`
D. `(2Mg)/(k)+x_(0)`

Answer

A

Explanation

For maximum displacement
`Mg(x) = 1/2k(2x)^(2) rArr x = (Mg)/(2k) rArr x = (mg)/(2k) - x_(0)`