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Two simple pendulums, having periods of ...

Two simple pendulums, having periods of `2s` and `3s` respectively, pass through the mean position simulaneously at a particular instant. They may be in phase after an interval of:

A

`5s`

B

`6s`

C

`1s`

D

none of these above

Text Solution

Verified by Experts

The correct Answer is:
B
`omega_(1) = (2pi)/(2) = pi` and `omega_(2) = ((2pi)/(3))`
They will be in phase if
`(omega_(t) - omega_(2)) t = 0, 2pi, 4pi`…..
`t = (2pi)/((omega_(1) - omega_(2))) = (2pi)/(pi - (2pi)/(3)) = 6` sec
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