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A particle executes SHM on a line 8 cm l...

A particle executes `SHM` on a line `8` cm long. Its `K.E.` and `P.E.` will be equal when its distance from the mean position is :-

A

`4 cm`

B

`2 cm`

C

`2 sqrt(2) cm`

D

`sqrt(2) cm`

Text Solution

Verified by Experts

The correct Answer is:
C
Here `1/2mv^(2) = 1/2kx^(2) rArr 1/2 momega^(2)(a^(2) - x^(2)) = 1/2momega^(2)x^(2)`
`rArr x = a/(sqrt(2)) = (4)/(sqrt(2)) = 2sqrt(2)cm`
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Knowledge Check

  • A particle executes SHM on a line 8 cm long . Its KE and PE will be equal when its distance from the mean position is

    A
    4 cm
    B
    2 cm
    C
    `2sqrt(2)` cm
    D
    `sqrt(2)` cm

  • A particle executing S.H.M. is given by x=10sin(8t+pi//3)m . Its velocity when it is at a distance 6 m from the mean position is,

    A
    36 m/s
    B
    10 m/s
    C
    80 m/s
    D
    64 m/s

  • In a S.H.M. with amplitude 'A', what is the ratio of K.E. and P.E. at (A)/(2) distance from the mean position ?

    A
    `1:4`
    B
    `3:4`
    C
    `3:1`
    D
    `1:3`

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