The magnitude of average accleration in half time period in a simple harmonic motion is

Options

A. `(2Aomega^(2))/(pi)`
B. `(Aomega^(2))/(2pi)`
C. `(Aomega^(2))/(sqrt(2)pi)`
D. zero

Answer

A

Explanation

`lt` acceleration `gt = (int_(0)^(T//2)omega^(2)asinomegatdt)/(int_(0)^(T//2)dt) = (2piomega^(2))/(pi)`