If the binding energy per nucleon in .(3...

If the binding energy per nucleon in `._(3)Li^(7)` and `._(2)He^(4)` nuclei are respectively `5.60` MeV and `7.06` MeV, then the ebergy of proton in the reaction `._(3)Li^(7) +p rarr 2 ._(2)He^(4)` is

`29.6 MeV`

`2.4 MeV`

`8.4 MeV`

`17.3 MeV`

Text Solution

Verified by Experts

The correct Answer is:

`Q = -7(5.6) + [4(7.06)]2 rArr Q = 17.3 MeV`

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