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Disintegration constant of a radioactive...

Disintegration constant of a radioactive material is `lambda`:

A

Its half life equal to `(log_(e)2)/(lambda)`

B

It mean life equals to `(1)/(lambda)`

C

At time equal to mean life, `63%` of the Initial radioactive material is left undecayed

D

After `3-` half 1/3 rd of the initial radioactive material is left undecayed.

Text Solution

Verified by Experts

The correct Answer is:
A, B
`N = N_(0)e^(-lambdat) rArr (N_(0))/(10) = N_(0)e^(-lambdaT_(1//2))`
`rArr T_(1//2) = (log_(e)2)/(lambda) rArr T_(mean) = (1)/(lambda)`
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Knowledge Check

  • Disintegration constant for a radioactive substance is 0.58 hr^(-1) . If half-life period

    A
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    B
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    `lamda T = 1`
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    `lamda T = 0.693`
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    D
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    A
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    B
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    C
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    D
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