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A nucleus undergoes a series of decay ac...

A nucleus undergoes a series of decay according to the scheme `A overset(alpha)(rarr) B overset(beta)(rarr)C overset(alpha)(rarr)D overset(gamma)(rarr) E`
Atomic number and mass number of E are 69 and 172

A

Atomic number of A is 72

B

Mass number of B is 176

C

Atomic number of D is 69

D

Atomic number of C is 69

Text Solution

Verified by Experts

The correct Answer is:
B, C

Assuming `beta` to be `_(+1)beta^(0)`
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Knowledge Check

  • In the decay process: A overset(- alpha)rarr B overset(-beta)rarr C overset(-beta)rarr D

    A
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    B
    `A` and `C` are isotones
    C
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    D
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    A
    `|overset(rarr)C|` is always greater then `|overset(rarr)A|` and `|overset(rarr)C| lt |overset(rarr)B|`
    B
    it is possible to have
    C
    `|overset(rarr)C|` is always equal to `|overset(rarr)A + overset(rarr)B|`
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    `|overset(rarr)C|` is never equal to `|overset(rarr)A+overset(rarr)B|`
  • Choose the correct symbols : RNA overset(a)(rarr) DNA overset(b)(rarr) DNA overset(c)(rarr) mRNA overset(d)(rarr) Polypeptide

    A
    a = Replication, b = Transcription, c = Translation, d = Transduction
    B
    a = Reverse transcription, b = Translation, c = Transcription, d = Replication
    C
    a = Replication, b = Transformation, c = Transcription, d = Translation
    D
    a = Reverse transcription b = Replication, c = Transcription, d = translation
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