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mark out the enthalpy for the formation of carbon . Monoxide (CO) given , `C(s)=1/2 O_(2)(g) to CO(g), DeltaH= -393 . 3 kJ // mol`
` CO(g)+ 1/2 O_(2)(g) to CO_(2)(g), DeltaH= - 282 kJ//mol`

A

110.5 kJ/mol

B

676.1 kJ / mol

C

282.8 kJ / mol

D

300.0 kJ/mol

Text Solution

Verified by Experts

The correct Answer is:
a
`C(s)+1/2O_(2)(g)toCO(g)`
the abov equation can be obtained by subraction of
`CO(g)+1/2O_(2)(g)to CO_(2)(g), DeltaH=-282.8kJ mol^(-1)`
from `C(s)+O_(2)(g)to Co(g), DeltaH=-393.3 kJ mol^(-1)`
`DeltaH_(t)=[+ 393.3 (282.8)] =110.5 kJ mol^(-1)`
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