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.(90)Th^(234) disintegrates to give .(82...

`._(90)Th^(234)` disintegrates to give `._(82)Pb^(206)Pb` as the final product. How many alpha and beta particles are emitted during this process ?

A

7 and 6

B

6 and 7

C

2 and 4

D

4 and 2

Text Solution

Verified by Experts

The correct Answer is:
A
Suppose the number of `lambda` particles emitted are 'x' and `beta` particles emitted are 'y' . Then,
`Th_(90)^(234) rarrPb_(82)^(206) + x^(4) ._(+2)alpha + y^(0) ._(-1)beta`
On equating mass number on both sides,
`234=206+4x+0y`
Or `x=7`
On equating atomic number on both sides,
`90=82+2x-y=82+2.7-y`
Or `y=6`
So, `7alpha and 6 beta` particles are emitted.
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