An old piece of wood has 25.6% as much `C^(14)` as ordinary wood today has. Find the age of the wood. Half-life period of `C^(14)` is 5760 years?

Explanation

'a'=amount of `.^(14)C` present originally in wood
Amount of `.^(14)C` now present in old wood`=(axx x)=(25.6)/(100)a=0.256a`
`:.` time 't' in which 'a' has changed to 0.256 a is
`t=(2.303)/(lambda)"log"(1)/(0.256 a)`
Now, `lambda=0.693//5760=1.203xx10^(-4) y^(-1)`
`t=(2303)/(1.203xx10^(-4)) "log" (1)/(0.256) rArrt=11329`years