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Helium nuclei combines to form an oxyge...

Helium nuclei combines to form an oxygen nucleus. The energy released per nucleon of oxygen nucleus is if `m_(0)=15.834` amu and `m_(He)=4.0026 `amu

A

`10.24 MeV`

B

0MeV

C

`5.24 MeV`

D

4 MeV

Text Solution

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The correct Answer is:
A
`4 ._(2)He^(4) rarr _(8)O^(16)`
Mass defect `=4 xx 4.0026 -15.834 a.m.u.=0.1764 a.m.u.`
Total energy released `=0.1764 xx 931 `MeV
Energy released /Nucleon`=(0.1764 xx 931)/(16)=10.24 `MeV
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