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The analysis of a uranium reveals that r...

The analysis of a uranium reveals that ratio of mole of `.^(206)Pb`and `.^(238) U` in sample is 0.2 . If effective decay constant of process `.^(238)U rarr .^(206) Pb` is `lambda` then age of rock is

A

`(1)/(lambda) In (5)/(4)`

B

`(1)/(lambda) In ((5)/(1))`

C

`(1)/(lambda) In(4)/(1)`

D

`(1)/(lambda) In ((6)/(5))`

Text Solution

Verified by Experts

The correct Answer is:
D

In the rock `("Moles of ".^(206)Pb)/("Moles of " .^(238 )U)=0.2=(0.2)/(1)`
`{:(,.^(238)U,rarr,.^(206)Pb,),("Initial moles",1.2 "mole*",,0,"(*calculate by moles of"),(,1"mole",,0.2 "mole","U left & moles of Pb formed) "):}`
`" " t=(1)/(lambda) ln ((1.2)/(1))=(1)/(lambda)ln ((6)/(5))`
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