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There is a stream of neutrons with KE=2e...

There is a stream of neutrons with KE=2eV. If the half life of neutrons is 100 sec, what fraction of neutrons will decay before they travel a distance of 1000 km. [Mass of neutrons `=1.6 xx10^(-24)g`]

A

`0.75`

B

`0.25`

C

`0.707`

D

`0.293`

Text Solution

Verified by Experts

The correct Answer is:
D

`(1)/(2)MV^(2) rArr 2 eV`
`V=sqrt((4eV)/(m))`
`V=sqrt((4eV)/(1.6 xx 10^(-27))) " " l eV=1.6 xx 10^(-19)J`
`sqrt((4 xx1.6 xx 10^(-19 )J)/(1.6 xx 10^(-27))) rArr V= sqrt(4 xx 10^(8))=2 xx 10^(4)m//s`
`t=(1000 xx 1000m)/(V) rArr t= (10^(6)m)/(2 xx 10^(4))= 50 sec`
`t=(t_(1//2))/(ln2) ln .(1)/((1-x)) rArr 50 = (100)/(ln2)ln .(1)/(1-x) rArr x=0.293`
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