Find the decay constant of `.^(55)Co` radio nuclide if its activity is known to decrease `4%` per hour. The decay product is non-radioactive.

Answer

[1500]

Explanation

`t_("avg")=(1)/(lambda) " " lambda xx 1 =ln(100)/(96) " " lambda=0.04 hr^(-1)`
`t_("avg")=(1)/(lambda)=25 xx60 xx=1500`