The total number of `alphaandbeta` particles emitted in the nuclear reaction
`""_(92)^(238)Uto""_(82)^(214)Pb` is

Answer

8

Explanation

`._(92)^(238)Urarr._(82)^(214)Pb +x._(2)He^(4)+y ._(-1)e^(0)`
Applying mass number balance
`238=214 +4x " " x=6`
Applying nuclear charge balance
`92=82+2x-y`
`92=82+12-y`
`y=2`
Total no. of `alpha` & `beta` particle emitted=8