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The number of neutrons emitteed when .(9...

The number of neutrons emitteed when `._(92)^(235)U` undergoes controlled nulclear fission to `._(54)^(142)Xe` and `._(38)^(90)Sr` is:

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The correct Answer is:
4
`._(92)^(235)U+._(0)n^(1) rarr ._(54)^(142) Xe+._(38)^(142)Xe+._(38)^(90)Sr+x ._(0)n^(1)`
Applying mass number balance
`235+1=142+90+x`
`x=4`
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