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Benzene burns according to the following...

Benzene burns according to the following equation
`2C_(6)H_(6)(l)+15 O_(2)(g) rarr 12 CO_(2) (g)+6H_(2)O(l)" "DeltaH^(@)= -6542 KJ`
What is the `DeltaE^(@)` for the combustion of `1.5` mol of benzene

A

`-3271 KJ`

B

`-9813 kJ`

C

`-4906.5 kJ`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
D
`Deltan=-3`
`DeltaH^(@)=DeltaE^(@)+(Deltan_(g))RT`
`rArr " "-6542=DeltaE^(@)+(-3)(8.31)(298)xx10^(-3)" "rArr" "DeltaE^(@)=-6534 kJ`
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