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The enthalpy of formation of enthane and...

The enthalpy of formation of enthane and benzene from the gaseous atoms are `-2839.2` and `-5506 kJ//mol` respectively. Bond enthalpy of `C = C` bond is
Given: Resonance energy of benzene `=-23.68" kJ/mol"`
Bond enthalpy of `C-H` bond `=411.0" kJ/mol"`

A

373.98 kJ/mol

B

632.24 kJ/mol

C

647.5 kJ/mol

D

1896.72 kJ/mol

Text Solution

Verified by Experts

The correct Answer is:
B
`-2839.2=0-[6xx411+DeltaH_(C-C)]`
`DeltaH_(C-C)=373.2" KJ/mol"`
`6C(g) +6H(g) rarr C_(6)H_(6)(g)`
`DeltaH_("theoritical")=0-[6xx411+3xx373.2+3x]`
`R.E.="Actual"-"Theoritical"`
`-23.68=-5506+[6xx411+3xx373.2+3x]`
`3x=5506-23.68-2466-1119.6`
`x=632.24" KJ/mol "`or`" "DeltaH_(C-C)=632.24" KJ/mol"`
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