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If enthalpy of hydrogenation of C(6)H(6)...

If enthalpy of hydrogenation of `C_(6)H_(6)(l)` into `C_(6)H_(12)(l)` is `-205 kJ` & resonance energy of `C_(6)H_(6)(l)` -152 kJ/mol then enthalpy of hydrogenation of 1, 4-cyclohexadiene `(l)` is
Assume `DeltaH_("vap")` of `C_(6)H_(6)(l), C_(6)H_(8)(l), C_(6)H_(12) (l)` all are equal

A

`-535.5` kJ/mol

B

`-238` kJ/mol

C

`-357` kJ/mol

D

None

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The correct Answer is:
B
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If enthaopy of hydrogenation of C_(6)H_(6)(l) into C_(6)H_(12)(l) is -205kJ//mol and resonance energy of C_(6)H_(6)(l) is -152kJ//mol then enthaopy of hydrogenation of Assume DeltaH_("vap") of C_(6)H_(6)(l),C_(6)H_(8)(l) all equal :

Calculate the enthalpy of combustion of benzene (l) on the basis of the following data: a. Resonance energy of benzene (l) =- 152 kJ// mol b. Enthalpy of hydrogenation of cyclohexene (l) =- 119 kJ//mol c. Delta_(f)H^(Theta)C_(6)H_(12)(l) =- 156 kJ mol^(-1) d. Delta_(f)H^(Theta) of H_(2)O(l) =- 285.8 kJ mol^(-1) e. Delta_(f)H^(Theta)of CO_(2)(g) =- 393.5 kJ mol^(-1)

For the reaction , 2C_(2)H_(6)(g)+7O_(2)(g)rarr4CO_(2)(g)+6H_(2)O(l) , the rate of disappearnce of C_(2)H_(6)(g) :

C_(6)H_(6) rarr C_(6)H_(12)Delta H = -204 KJ heat of hydrognentaion of each C=C bond in benzene

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