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Using the bond enthalpy data given below...

Using the bond enthalpy data given below, calculate the enthalpy change for the reaction.
`C_(2)H_(4)(g)+H_(2)(g) rarr C_(2)H_(6) (g)`
`("Bond",C-C,C=C,C-H,H-H),("Bond Enthalpy",336.81" kJ/mol",606.68" kJ/mol",410.87" kJ/mol",431.79" kJ/mol",):}`

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The correct Answer is:
`-120.08` kJ/mol
`DeltaH[606.68+(4xx410.87)+431.79]-[(336.81+(6xx410.87)]=-120.08" kJ mol"^(-1)`
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