The heat of solution of anhydrous `CuSO_(4)` is -15.9 kcal and that of `CuSO_(4).5H_(2)O` is 2.8 kcal. The heat of hydration of `CuSO_(4)` will be

Answer

`-18.7` kCal/mole

Explanation

`CuSo_(4) + (aq) rarr CuSO_(4) (aq)`
`CuSO_(4).5H_(2)O (s) + (aq) rarr CuSO_(4) (aq) " " Delta H = 2.8`
`Delta H` for taget reaction `= - 15.9 - 2.8 = - 18.7 k cal//"mole"`