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Calculate the enthalpy of combustion of ...

Calculate the enthalpy of combustion of benzene `(l)` on the basis of the following data:
a. Resonance energy of benzene `(l) =- 152 kJ// mol`
b. Enthalpy of hydrogenation of cyclohexene `(l) =- 119 kJ//mol`
c. `Delta_(f)H^(Theta)C_(6)H_(12)(l) =- 156 kJ mol^(-1)`
d. `Delta_(f)H^(Theta) of H_(2)O(l) =- 285.8 kJ mol^(-1)`
e. `Delta_(f)H^(Theta)of CO_(2)(g) =- 393.5 kJ mol^(-1)`

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Verified by Experts

The correct Answer is:
`DeltaH_(C)^(@) ("benzene")=-3267.4" kJ mol"^(-1)`

Resonance energy = observed energy - calculated energy
Calculate energy `=-3419.4`
Observed `=-3419.4-(-152)=-3267.4" kJ mol"^(-1)`
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The enthalpy of hydrogenation of cyclohexene is -119.5kJ mol^(-1) . If resonance energy of benzene is -150.4kJ mol^(-1) , its enthalpy of hydrogenation would be :

Calculate the resonance energy of gaseous benzene form the following data. BE(C-H) = 416.3 kJ mol^(-1) BE(C-C) = 331.4 kJ mol^(-1) BE(C=C) = 591.1 kJ mol^(-1) Delta_("sub")H^(Theta)(C,"graphite") = 718.4 kJ mol^(-1) Delta_("diss")H^(Theta)(H_(2),g) = 435.9 kJ mol^(-1) Delta_(f)H^(Theta) ("benzene", g) = 82.9 kJ mol^(-1)

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