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Calculate the enthalpy change for the fo...

Calculate the enthalpy change for the following reaction:
`XeF_(4) rarr Xe^(o+) +F^(Theta) +F_(2) +F`. The average `Xe-F` bond energy is `34 kcal mol^(-1)`, first `IE` of `Xe` is `279 kcal mol^(-1), EA` of `F` is `85 kcal mol^(-1)` and bond dissociation enegry of `F_(2)` is `38 kcal mol^(-1)`

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The correct Answer is:
292 kCal/mol

`DeltaH=136+279-85-38=292`
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