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Given {:("Reaction","Energy Change (in ...

Given `{:("Reaction","Energy Change (in KJ)",),(Li(s) rarr Li(g),161,),(Li(g) rarr Li^(+) (g),520,),((1)/(2) F_(2)(g) rarr F(g),77,),(F(g) + e^(-) rarr F(g),("Electron gain enthalpy"),),(Li^(+) (g) + F^(-)(g) rarr LiF(s),-1047,),(Li (s) + (1)/(2) f_(2) (g) rarr LiF(s),-617,):}`
Based on data provided, the value of electron gain enthalpy of fluorine would be :

A

`-300 kJ mol^(-1)`

B

`-228 kJ mol^(-1)`

C

`-328 kJ mol^(-1)`

D

`-350 kJ mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C

`Li (s) + (1)/(2)F_(2) (g) rarr LiF(s) = - 617`
`DeltaH = -617 = 161 + 520 + 77 + x - 1047`
`x = -328 kJ mol^(-1)`
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