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Given the following information : A^(-...

Given the following information :
`A^(-)(g) rarr A^(2+) (g) + 3e^(-) DeltaH_(1) = 1400 KJ//"mole"`
`A (g) rarr A^(2+) (g) + 2e^(-) DeltaH_(2) = 700 KJ//"mole"`
`DeltaH_(eg) [A^(+)(g)] = -350 KJ//"mole"`
`IE_(1) + IE_(2)` for `A (g) = 950 KJ//"mole"`
The value of `IE_(1)` of `A^(-)` in KJ/mol is :

A

450

B

`+350`

C

`+600`

D

`+ 250`

Text Solution

Verified by Experts

The correct Answer is:
B

`{:(A^(-)(g)rarrA(g)+e,,DeltaH_(eg)=-350 "kJ/mole"),(A^(+)(g)+e^(-)rarrA,,):}`
`{:(A^(-)rarrA+e^(-)),(ArarrA^(+)+e^(-)),(A^(+)rarrA^(+2)+e^(-)):}}1400 "kJ/mole"....("i")`
`{:(ArarrA^(+)+e^(-)),(A^(+)rarrA^(+2)+e^(-)):}}IE_(1)+IE_(2) "of" A = 950 "kJ/mole" ....("ii")`
Comparing (i) and (ii)
`A^(-)rarrA+e^(-)rArr 450 "kJ/mole"`
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From the following information {:(A^(-)(g)rarrA^(+2)(g)+3e^(-),DeltaH_(1) = 1400 kJ//"mole"),(A(g)rarrA^(+2)(aq)+2e^(-),DeltaH_(2) = 700 kJ//"mole"),(DeltaH_(EG)[A^(+)(g)] =- 350 kJ//mol,),((IE_(1)+IE_(2))for A(g) = 950kJ//mol,):} Find (a) IE_(1) of A (b) IE_(2) of A (c) DeltaH_(EG) of A (d) DeltaH_(HE) of A^(2+)(g)

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