Calculate total number of electron present in Cr having `n + l + m = 6`

Options

A. 3
B. 1
C. 5
D. 6

Answer

B

Explanation

`Cr_(24) = 1s^(2) 2p^(6) 3s^(2) underset(3 + 1 + 1 = 5)underset(darr)(3p^(6)) " " underset(("one 'd' orbital"))underset(3 + 2 + 1 = 6)underset(darr)(3d^(5)4s^(1))`
Number of electrons having `n + l + m = 6` from `3d^(5) = 1`
Total `=1`