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Total number of valence electrons presen...

Total number of valence electrons present in `6.4 gm` of peroxide ion `O_(2)^(-2)` is -

A

`2.8 N_(A)`

B

`3.2 N_(A)`

C

`0.2 N_(A)`

D

`3.6 N_(A)`

Text Solution

Verified by Experts

The correct Answer is:
A
Mole `= (6.4)/(32) = 0.2`
Number of valence electrons in `O_(2)^(2) = 14`
Total number of valence electron `= 0.2 xx 14 xx N_(A) = 2.8 N_(A)`
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