Amount of `80%` pure NaOH sample which is required to completely react with `42.6 gm` Chlorine in hot condition according to given reaction
`NaOH + Cl_(2) rarrNaCl + H_(2)O + O_(2)` is -

Options

A. 48
B. 60 gm
C. 24 gm
D. 30 gm

Answer

B

Explanation

`2NaOH + Cl_(2) rarr 2NaCl + H_(2)O + (1)/(2) O_(2)`
`1.2` mole `0.6` mole
`n_(NaOH "pure required") = 1.2`
`W_(NaOH "pure") = 1.2 xx 40 = 48 gm`
`W_("impure sample") xx (80)/(100) = W_(NaOH "pure")`
`W_("sample") = 60 gm`