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At what temperature would CO(2) molecule...

At what temperature would `CO_(2)` molecule have an rms speed equal to `H_(2)` at `27^(@) C`.

A

`4400 K`

B

`2200 K`

C

`6600K`

D

`1100 K`

Text Solution

Verified by Experts

The correct Answer is:
C
`rms_(CO_(2)) = rms_(H_(2))`
`(sqrt((3RT)/(M)))_(CO_(2)) = (sqrt((3RT)/(M)))_(H_(2))`
`(3 xx R xx T)/(44) = (3 xx R xx 300)/(2)`
`T = 6600 K`
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