If degree of dissociation of HI is `0.1` then `K_(P)` for reaction is:
`2HI (g) Harr H_(2) (g) + I_(2) (g)`

Options

A. `(1)/(9)`
B. `(1)/(324)`
C. `(10)/(36)`
D. can't be determined

Answer

B

Explanation

`{:(,2HI,hArr,H_(2),+,I_(2),,),("moles",a_(0) - a_(0) alpha,,(a_(0) alpha)/(2),,(a_(0) alpha)/(2),alpha = 0.1 "(given)",),(" at" eq^(m),,,,,,,):}`
`K_(p) = K_(C )` as `(Delta n)_(g) = 0`
`K_(P) = (alpha^(2))/(4 (1 - alpha)^(2)) = ((0.1)^(2))/(4(1 - 0.1)^(2)) = ((0.1)^(2))/(4 xx (0.9)^(2))`
`= (1)/(81 xx 4)`
`K_(P) = (1)/(324)`