The correct IUPAC name of the following compound is :
`O = underset(OH)underset(|)(C)-CH_(2) -underset(H-C = O)underset(|)(CH) - CHO`

Options

A. 3,3 -diformyl propanoic acid
B. 3-formyl-4-oxo-butanoic acid
C. 3,3-dioxo propanoic acid
D. 3,3-dicarbadehyde propanoic acid

Answer

To determine the correct IUPAC name of the given compound, we will follow these steps:

### Step 1: Identify the Functional Groups
The compound has two aldehyde (CHO) groups and one carboxylic acid (COOH) group.

### Step 2: Determine the Longest Carbon Chain
We need to find the longest continuous carbon chain that includes the functional groups. In this case, the longest chain consists of four carbon atoms.

### Step 3: Number the Carbon Chain
We will number the carbon chain starting from the end nearest to the carboxylic acid group, which has the highest priority. This gives us:
- Carbon 1: COOH (carboxylic acid)
- Carbon 2: CH
- Carbon 3: CHO (aldehyde)
- Carbon 4: CH2

### Step 4: Identify Substituents and Their Positions
- At carbon 3, there is an aldehyde group (CHO), which we denote as "4-oxo" when used as a prefix.
- At carbon 4, there is another aldehyde group (CHO), which we denote as "4-formyl" when used as a prefix.

### Step 5: Combine the Names
The IUPAC name will combine the substituents and the main chain name:
- The main chain is butane (4 carbon atoms).
- The carboxylic acid will be indicated as "oic acid" at the end of the name.
- The complete name is: **3,4-diformylbutanoic acid**.

### Final Answer
The correct IUPAC name of the compound is **3,4-diformylbutanoic acid**.

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