A meter bridge is set up as shown, to determine an unknown resistance `X` using a standard 10 ohm resistor. The galvanometer shows null point when tapping -key is at 52 cm mark. The end-corrections are 1 cm and 2 cm respectively for the ends A and B. The determine value of `X` is

Options

A. `10.2ohm`
B. `10.6ohm`
C. `10.8ohm`
D. `11.1ohm`

Explanation

`l_(1) = 52 + 1 = 53 cm`
`l_(2) = 48 + 2 = 50 cm`
`(l_(1))/(l_(2)) = (x)/(R) rArr (53)/(50) = (x)/(10)`
`x = 10.6 Omega` .