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The diameter of a cylinder is measured u...

The diameter of a cylinder is measured using a Vernier callipers with no zero error. It is found that the zero of the Vernier scale lies between `5.10cm and 5.15cm` of the main scale. The Vernier scale has `50` divisions equivalent to `2.45 cm`. The `24^(th)` division of the Vernier scale exactly coincides with one of the main scale divisions. the diameter of the cylinder is

A

`5.12 cm`

B

`5.124 cm`

C

`5.1236 cm`

D

`5.148 cm`

Text Solution

Verified by Experts

`50VCD =2.45 cm`
`1 VSD = (245)(50) cm = 0.049cm`
Least count of vernier `= 1MSD -1VSD`
`=0.05cm - 0.049 cm = 0.001cm`
Thickness of the object = Main scale reading + vernier reading x least count
`=5.10 + (24) (0.001) = 5.124 cm` .
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