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The function f(x) =cot x is discontinu...

The function `f(x) =cot x` is discontinuous on set

A

`{x=npi:ninZ }`

B

`{x = 2npi : n in Z }`

C

` {x =(2n+1)(pi)/(2),n in Z}`

D

`{x=(npi)/(2), n in Z}`

Text Solution

Verified by Experts

The correct Answer is:
A
We know that, `f(x) = cotx` is continuous in `R-{npi:ninZ}`.
Since, `f(x) = cotx = (cosx)/(sinx)`, [since, `sinx = 0` at `n pi, n in Z`]
Hence`f(x)= cotx` is discontinuous on the set ` {x=npi : n in Z}`.
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  3. The function f(x) =cot x is discontinuous on set

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  4. The function f(x) = e^(|x|) is

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  9. If y = sqrt(sinx+y), then (dy)/(dx) is equal to

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  13. For the function f(x) = x + 1/x, x in [1,3] , the value of c for me...

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  14. An example of a function which is continuous every where but fails to...

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  15. Derivative of x^(2) w.r.t. x^(3) is "……."

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  17. For the curve sqrt(x) + sqrt(y) = 1, (dy)/(dx) at (1/4,1/4) is "……….".

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  18. Rolle's theorem is applicable for the function f(x) = |x-1| in [0,2].

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  19. If f is continuous on its domain D; then |f| is also continuous on D

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  20. If f is continuous on its domain D; then |f| is also continuous on D

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