Find the LCM and HCF of the `26` and `91` and verify that
HCF`xx`LCM = product of the given two numbers.

Explanation

(i)
`:. 36=2xx2xx3xx3`
`48=2xx2xx3xx2xx2`
Now, HCF`=2xx2xx3=12`
and LCM`=2xx2xx3xx3xx2xx2=144`
Now HCF `xx` LCM=`12xx144=1728`
and product of two numbers `=36xx48=1728`
Hence, HCF `xx` LCM= product of two numbers. Hence verified
(ii)
`:. 60=2xx2xx3xx5`
`80=2xx2xx5xx2xx2`
Now, HCF `=2xx2xx5=20`
and LCM `=2xx2xx3xx5xx2xx2=240`
Now, HCF `xx`LCM`=20xx240=4800`
and product of two numbers `=60xx80=4800`
Hence, HCF `xx`LCM=product of two numbers. Hence Verified.
An Important Result
Product of two given numbers=Product of their HCF and LCM
This result is true only for two numbers.