What is the smallest number that, when divided by 35,56 and 91 leaves remainder of 7.

Explanation

A number is divided by 3 numbers, means `to` LCM of 3 number
`35=5xx7`
`56=2xx2xx2xx7`
`91=13xx7`
`:.` LCM`=5xx7xx2xx2xx2xx13=3640`
Rule: Take the first as it is . Then take the factors from second number which are not taken so far. Then take the factors of third number which are not taken so far.
`:.` Smallest number completely divisibility by 35,36 and 91 is 3640 .
Hence, smallest number which when divided by 35,56 and 91 leaves a remainder of 7 in each case will be 3640+7=3647 .