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Check whether 6^n can end with the digit...

Check whether `6^n` can end with the digit 0 for any natural number `n` .

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The correct Answer is:
No
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Assertion (A): 6^(n) ends with the digit zero where n is a natural number. Reason (R):Any number ends with digit zero, if its prime factor is of the form 2^(m)xx5^(n) , where m,n are natural numbers.

If 6^n - 5^n always end with a digit, where n is any natural number, then the desired digit is