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A number consists of two digits. The pro...

A number consists of two digits. The product of these digits is 14. If 45 is subtracated from the number, the digits interchange their places. Find the number.

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To solve the problem step by step, we will define the digits of the two-digit number and set up equations based on the information given. ### Step 1: Define the digits Let the two-digit number be represented as \(10x + y\), where \(x\) is the tens digit and \(y\) is the units digit. ### Step 2: Set up the equations According to the problem: 1. The product of the digits is 14: \[ xy = 14 \] 2. If 45 is subtracted from the number, the digits interchange their places: \[ 10x + y - 45 = 10y + x \] ### Step 3: Simplify the second equation Rearranging the second equation gives us: \[ 10x + y - 45 = 10y + x \] \[ 10x - x + y - 10y = 45 \] \[ 9x - 9y = 45 \] Dividing the entire equation by 9: \[ x - y = 5 \quad \text{(Equation 1)} \] ### Step 4: Express \(y\) in terms of \(x\) From the product equation \(xy = 14\), we can express \(y\) in terms of \(x\): \[ y = \frac{14}{x} \quad \text{(Equation 2)} \] ### Step 5: Substitute Equation 2 into Equation 1 Substituting \(y\) from Equation 2 into Equation 1: \[ x - \frac{14}{x} = 5 \] Multiplying through by \(x\) to eliminate the fraction: \[ x^2 - 14 = 5x \] Rearranging gives us a standard form quadratic equation: \[ x^2 - 5x - 14 = 0 \] ### Step 6: Solve the quadratic equation We can solve this quadratic equation using the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] where \(a = 1\), \(b = -5\), and \(c = -14\): \[ x = \frac{-(-5) \pm \sqrt{(-5)^2 - 4 \cdot 1 \cdot (-14)}}{2 \cdot 1} \] \[ x = \frac{5 \pm \sqrt{25 + 56}}{2} \] \[ x = \frac{5 \pm \sqrt{81}}{2} \] \[ x = \frac{5 \pm 9}{2} \] Calculating the two possible values for \(x\): 1. \(x = \frac{14}{2} = 7\) 2. \(x = \frac{-4}{2} = -2\) (not valid since \(x\) must be a digit) Thus, \(x = 7\). ### Step 7: Find \(y\) Substituting \(x = 7\) back into Equation 2 to find \(y\): \[ y = \frac{14}{7} = 2 \] ### Step 8: Form the two-digit number The two-digit number is: \[ 10x + y = 10(7) + 2 = 70 + 2 = 72 \] ### Final Answer The number is **72**.
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NAGEEN PRAKASHAN-QUADRATIC EQUATIONS-Exercise 4d
  1. Determine two consecutive multiples of 3 whose product is 270.

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  2. Three consecutive positive integers are such that the sum of the squar...

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  3. A number consists of two digits. The product of these digits is 14. If...

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  4. A two digit number is four times the sum and three times the product o...

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  5. In a two digit number, the ten's digit is bigger. The product of the d...

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  6. A two digit number is made of two consccutive digits such that the sum...

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  7. In a certain positive fraction, the denominator is greater than the nu...

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  8. The denominator of a positive fraction is one more than twice the nume...

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  9. The numerator of a fraction is 4 less than denominator. If 1 is add...

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  10. The numerator of a fraction is 4 less than denominator. If 1 is add...

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  11. The sides of a right angled triangle containing the right angle are 4x...

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  12. The hypotenuse of a right triangle is 13 cm and the difference between...

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  13. The longest side of a right angled triangle is 4cm longer than one sid...

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  14. In a tringle the measure of the greatest angle is square of measure ...

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  15. The hypotenuse of a right triangle is 3sqrt(10)c m . If the smaller...

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  16. A square lawn has a path 2m wide around it. The area of the path is 19...

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  17. The number of seats in a row is equal to the total number of rows in a...

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  18. The area of a recangular field is 260m^(2) . Had its length been 5 m l...

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  19. A chess board contains 64 equal squares and the area of each square...

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  20. A girl is twice as old as her sister. Four years hence, the product of...

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