Evaluate `(sin35^(@))/(cos55^(@))+(sec20^(@))/("cosec"70^(@))`.

Answer

To evaluate the expression \((\sin 35^\circ)/(\cos 55^\circ) + (\sec 20^\circ)/(\csc 70^\circ)\), we can follow these steps:

### Step 1: Simplify \(\sin 35^\circ\) and \(\cos 55^\circ\)
Using the co-function identity, we know that:
\[ \sin(90^\circ - x) = \cos x \]
Thus, we can write:
\[ \sin 35^\circ = \cos(90^\circ - 35^\circ) = \cos 55^\circ \]
So, \(\sin 35^\circ = \cos 55^\circ\).

### Step 2: Substitute into the expression
Now, substituting this into our expression gives:
\[ \frac{\sin 35^\circ}{\cos 55^\circ} = \frac{\cos 55^\circ}{\cos 55^\circ} = 1 \]

### Step 3: Simplify \(\sec 20^\circ\) and \(\csc 70^\circ\)
Next, we simplify \(\sec 20^\circ\) and \(\csc 70^\circ\):
\[ \csc 70^\circ = \frac{1}{\sin 70^\circ} \]
Using the co-function identity again:
\[ \sin 70^\circ = \cos(90^\circ - 70^\circ) = \cos 20^\circ \]
Thus, \(\csc 70^\circ = \frac{1}{\cos 20^\circ}\).

### Step 4: Substitute into the expression
Now we can rewrite the second part of the expression:
\[ \frac{\sec 20^\circ}{\csc 70^\circ} = \frac{\sec 20^\circ}{\frac{1}{\cos 20^\circ}} = \sec 20^\circ \cdot \cos 20^\circ \]
Since \(\sec 20^\circ = \frac{1}{\cos 20^\circ}\), we have:
\[ \sec 20^\circ \cdot \cos 20^\circ = 1 \]

### Step 5: Combine the results
Now we can combine both parts of the expression:
\[ 1 + 1 = 2 \]

### Final Answer
Thus, the evaluated result is:
\[ \boxed{2} \]