Find the equation of parabola whose focus is (2,0) and equation of directrix is x=-2.

Explanation

Equation of directrix x=-2
`rArr" "x+2=0`
Let P(x, y) be any point on the parabola.
Therefore, from the definition of parabola distance of from focus = perpendicular distance from p to directrix.
`rArr" "sqrt((x-2)^(2)+(y-0)^(2))=x+2`
`rArr" "(x-2)^(2)+y^(2)=(x+2)^(2)`
`rArr" "y^(2)=8x`.