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In pure semiconductor, the number of con...

In pure semiconductor, the number of conduction electrons is `6 xx 10^18` per cubic meter. How many holes are there in a sample of size 1 cm x 1 cm x 1 mm?

A

`3xx10^10`

B

`6xx10^11`

C

`3xx10^11`

D

`6xx10^10`

Text Solution

AI Generated Solution

The correct Answer is:
To find the number of holes in a pure semiconductor sample of size 1 cm x 1 cm x 1 mm, we can follow these steps: ### Step 1: Determine the volume of the sample The dimensions of the sample are given as: - Length = 1 cm - Width = 1 cm - Height = 1 mm First, we need to convert these dimensions into meters: - 1 cm = 0.01 m - 1 mm = 0.001 m Now, we can calculate the volume in cubic meters: \[ \text{Volume} = \text{Length} \times \text{Width} \times \text{Height} = (0.01 \, \text{m}) \times (0.01 \, \text{m}) \times (0.001 \, \text{m}) = 0.0000001 \, \text{m}^3 = 1 \times 10^{-7} \, \text{m}^3 \] ### Step 2: Calculate the number of conduction electrons The number of conduction electrons per cubic meter is given as: \[ n = 6 \times 10^{18} \, \text{electrons/m}^3 \] To find the total number of conduction electrons in the sample, we multiply the number of electrons per cubic meter by the volume of the sample: \[ \text{Total electrons} = n \times \text{Volume} = (6 \times 10^{18} \, \text{electrons/m}^3) \times (1 \times 10^{-7} \, \text{m}^3) \] \[ \text{Total electrons} = 6 \times 10^{11} \, \text{electrons} \] ### Step 3: Determine the number of holes In a pure semiconductor, the number of holes is equal to the number of conduction electrons. Therefore, the number of holes in the sample is also: \[ \text{Total holes} = 6 \times 10^{11} \, \text{holes} \] ### Final Answer The number of holes in the sample is \( 6 \times 10^{11} \). ---

To find the number of holes in a pure semiconductor sample of size 1 cm x 1 cm x 1 mm, we can follow these steps: ### Step 1: Determine the volume of the sample The dimensions of the sample are given as: - Length = 1 cm - Width = 1 cm - Height = 1 mm ...
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