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The depth 'd' at which the value of acce...

The depth 'd' at which the value of acceleration due to gravity becomes `(1)/(n)` times the value at the earth's surface is (R = radius of earth)

A

`d = R((n)/(n-1))`

B

`d = R((n-1)/(2n))`

C

`d = R((n-1)/(n))`

D

`d = R^2((n-1)/(n))`

Text Solution

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The correct Answer is:
C
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