A uniform force of 4 N acts on a body of mass 10 kg for a distance of 2.0 m . The kinetic energy acquired by the body is

Options

A. 16 J
B. `32xx10^8` erg
C. 8 J
D. 32 erg

Answer

To solve the problem, we will use the Work-Energy Theorem, which states that the work done on an object is equal to the change in its kinetic energy.

### Step-by-step Solution:

1. **Identify the Given Values:**
- Force (F) = 4 N
- Mass (m) = 10 kg
- Displacement (d) = 2 m

2. **Calculate the Work Done (W):**
The work done by the force can be calculated using the formula:
\[ W = F \times d \]
Substituting the values:
\[ W = 4 \, \text{N} \times 2 \, \text{m} = 8 \, \text{J} \]

3. **Apply the Work-Energy Theorem:**
According to the Work-Energy Theorem:
\[ W = \Delta KE = KE_{\text{final}} - KE_{\text{initial}} \]
Since the body starts from rest, the initial kinetic energy (KE_initial) is 0. Therefore:
\[ W = KE_{\text{final}} - 0 \]
This simplifies to:
\[ KE_{\text{final}} = W \]

4. **Calculate the Final Kinetic Energy:**
From the work done calculated in step 2:
\[ KE_{\text{final}} = 8 \, \text{J} \]

Thus, the kinetic energy acquired by the body is **8 Joules**.