The potential energy of a particle varies with distance `x` from a fixed origin as `U = (A sqrt(x))/( x^(2) + B)`, where `A and B` are dimensional constants , then find the dimensional formula for `AB`.

Options

A. `[ML^((5)/(2))T^(-2)]`
B. `[M^(1)L^(2)T^(-2)]`
C. `[M^((3)/(2))L^((5)/(2))T^(-2)]`
D. `[M^(1)L^((7)/(2))T^(-2)]`

Answer

D