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The potential energy of a 1kg particle f...

The potential energy of a 1kg particle free to move along the x-axis is given by `V(x)=(x^(4)/4-x^(2)/2)J` The total mechanical energy of the particle is 2J then the maximum speed (in `m//s)` is

A

`(4)/(sqrt2)`

B

`(1)/(sqrt2)`

C

`(3)/(sqrt2)`

D

2

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The correct Answer is:
C
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