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If 0.1 J of energy is stored for the flow of the current of 0.2 A in an inductor, then its inductance value (in H) is

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To find the inductance value \( L \) of an inductor given that 0.1 J of energy is stored for a current of 0.2 A, we can use the formula for the energy stored in an inductor: \[ E = \frac{1}{2} L I^2 \] where: - \( E \) is the energy stored in the inductor (in joules), - \( L \) is the inductance (in henries), - \( I \) is the current flowing through the inductor (in amperes). ### Step-by-Step Solution: 1. **Identify the given values**: - Energy \( E = 0.1 \, \text{J} \) - Current \( I = 0.2 \, \text{A} \) 2. **Substitute the known values into the energy formula**: \[ 0.1 = \frac{1}{2} L (0.2)^2 \] 3. **Calculate \( (0.2)^2 \)**: \[ (0.2)^2 = 0.04 \] 4. **Rewrite the equation with the calculated value**: \[ 0.1 = \frac{1}{2} L (0.04) \] 5. **Multiply both sides by 2 to eliminate the fraction**: \[ 0.2 = L (0.04) \] 6. **Solve for \( L \)** by dividing both sides by 0.04: \[ L = \frac{0.2}{0.04} \] 7. **Calculate the value of \( L \)**: \[ L = 5 \, \text{H} \] ### Final Answer: The inductance value \( L \) is \( 5 \, \text{H} \). ---
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