Four particles, each of mass m and charge q, are held at the vertices of a square of side 'a'. They are released at t = 0 and move under mutual repulsive forces speed of any particle when its distance from the centre of square doubles is

Options

A. `[(1)/(4piepsilon_(0))(q^(2))/(ma)(1+(1)/(2sqrt(2)))]^(1//2)`
B. `[(1)/(4piepsilon_(0))(q^(2))/(ma)]^(1//2)`
C. `[(1)/(4piepsilon_(0))(q^(2))/(ma^(2))]^(1//2)`
D. `[(1)/(4piepsilon_(0))(q^(2))/(ma^(2))(1+(1)/(2sqrt(2)))]^(1//2)`

Answer

A