The final product (Z) is the following sequence of reaction `CH_3CH_2NH_2overset(HNO_2)rarr(X)overset(Socl_2)rarr(Y) " is " overset(NH_3)rarr(Z)`

Options

A. methanamine
B. ethanamide
C. ethanamine
D. propan-1- amine

Answer

To solve the given sequence of reactions, we will go through each step carefully.

### Step 1: Reaction of Ethylamine with Nitrous Acid
The starting compound is ethylamine, which has the structure CH₃CH₂NH₂. When ethylamine reacts with nitrous acid (HNO₂), it undergoes a diazotization reaction. This reaction occurs at low temperatures (around 0°C) and leads to the formation of a diazonium salt.

**Reaction:**
\[ \text{CH}_3\text{CH}_2\text{NH}_2 + \text{HNO}_2 \rightarrow \text{CH}_3\text{CH}_2\text{N}_2^+ + \text{HCl} + \text{H}_2\text{O} \]

Since ethylamine is an aliphatic amine, the diazonium salt formed is unstable and will decompose in the presence of water to form an alcohol.

**Product (X):**
\[ \text{X} = \text{CH}_3\text{CH}_2\text{OH} \] (ethanol)

### Step 2: Reaction of Alcohol with Thionyl Chloride
Next, we take the alcohol (X) and react it with thionyl chloride (SOCl₂). This reaction converts the alcohol into an alkyl chloride through a nucleophilic substitution mechanism.

**Reaction:**
\[ \text{CH}_3\text{CH}_2\text{OH} + \text{SOCl}_2 \rightarrow \text{CH}_3\text{CH}_2\text{Cl} + \text{SO}_2 + \text{HCl} \]

**Product (Y):**
\[ \text{Y} = \text{CH}_3\text{CH}_2\text{Cl} \] (ethyl chloride)

### Step 3: Reaction of Alkyl Chloride with Ammonia
Now, we take the alkyl chloride (Y) and react it with ammonia (NH₃). In this reaction, the ammonia acts as a nucleophile and substitutes the chlorine atom, forming an amine.

**Reaction:**
\[ \text{CH}_3\text{CH}_2\text{Cl} + \text{NH}_3 \rightarrow \text{CH}_3\text{CH}_2\text{NH}_2 + \text{HCl} \]

**Product (Z):**
\[ \text{Z} = \text{CH}_3\text{CH}_2\text{NH}_2 \] (ethylamine)

### Final Answer
The final product (Z) of the sequence of reactions is ethylamine (CH₃CH₂NH₂).

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