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The lattice energy of solid NACl is 180K...

The lattice energy of solid `NACl` is `180K. Cal mol^(-1)`. The dissolution of the solid in water in the form of ions is endothermic to the extent of `1 K.cal mol^(-1)`. If the hydration energies of `NA^(+)` and `Cl^(-)` are in ratio `6 : 5`, what is the enthalpy of hydration of `NA^(+)` ion

A

`-8.5 " kcal mol"^(-1)`

B

`-97.64 " kcal mol"^(-1)`

C

`+82.6" kcal mol"^(-1)`

D

`+100 " kcal mol"^(-1)`

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The correct Answer is:
B
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