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The de-Brogile wavelength of a neutron a...

The de-Brogile wavelength of a neutron at `927^(@)`C is `lamda`. What will be its wavelength at `27^(@)`C?

A

`lamda/2`

B

`lamda`

C

`2lamda`

D

`4lamda`

Text Solution

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The correct Answer is:
C
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Knowledge Check

  • The de - Broglie wavelength of a neutron at 27 ^(@) C is lambda . What will be its wavelength at 927^(@) C ?

    A
    `lambda//2`
    B
    `lambda//3`
    C
    `lambda//4`
    D
    `lambda//9`

  • The de-Broglie wavelength of a neutron at 1327^@C is lambda . What will be its wavelength at 127^@C ?

    A
    `lambda`
    B
    `2 lambda`
    C
    `lambda/2`
    D
    `8lambda`

  • The de-Broglie wavelength lamda

    A
    is proportional to mass
    B
    is proportional to impulse
    C
    Inversely proportional to impulse
    D
    does not depend on impulse
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